[Math Lair] Solutions for Practice Test 9, The Official SAT Study Guide, Section 2

Math Lair Home > Test Preparation > Solutions for Practice Test 9, The Official SAT Study Guide, Section 2
SAT Practice Test Solutions:
2014–15 SAT Practice Test
2013–14 SAT Practice Test
The Official SAT Study Guide, second edition
SAT Math Tips

Here are solutions for section 2 of practice test #9 in The Official SAT Study Guide, second edition, found on pages 886–891. The solutions below demonstrate faster, more informal methods that might work better for you on a fast-paced test such as the SAT. To learn more about these methods, see my e-book Succeeding in SAT Math or the SAT math tips page.

  1. The numbers 32 and 33 are in both set X and set Y. So, there are 2 numbers. Select (A) Two.
  2. If Linda travelled twice as far in half the time, then Linda travelled 20 miles in 1 hour. So, her average speed was 20 miles per hour. Select (C) 20.
  3. If x = k(k − 2), then x + 1 = k(k − 2) + 1 = k² −2k + 1. Select (C) k² −2k + 1.
  4. From the Reference Information, the length of the hypotenuse of the right triangle is x2. So, the perimeter of the triangle is 2x + x2. We are told that the perimeter is equal to 4 2√2, so by inspection x = 2. Select (A) 2.
  5. If 20 minutes out of 60 was commercials, then 40/60, or 2/3, was not commercials. Enter 2/3.
  6. Convert the sentence into an equation:
    If[ignore]
    the product of ... and×
    0.30.3
    a numberx
    is equal to=
    11
    Putting this together, we get:
    0.3 × x = 1
    x = 1/0.3
    x = 10/3
    Enter 10/3.
  7. Substitute the numbers x = 10, y = 3 and z = 5 into xyzy, resulting in:
      10³ − 5³
    = 1000 − 125
    = 875
    Enter 875.
  8. Guess and check: Try values for UT until you find one that makes the area of PQST greater than 10 but less than 30. Start with, say, UT = 2. Then, PT is 7 and ST = 2, so the area of PQST is 14, which works. Enter 2.
  9. If there were half as many green balloons as red balloons, and ⅓ of the balloons are red, then 1/6 of the balloons are green. Since each balloon is either red, green, or blue, then 1 − ⅓ − 1/6 = ½ of the balloons are blue. Since 18 of the balloons are blue, then there are 18 ÷ ½ = 36 balloons in total. Enter 36.
  10. 2x + 2x + 2x + 2x = 27
    4(2x) = 27
    2²(2x) = 27
    2x = 25
    x = 5
    Enter 5.
  11. If the average of these five numbers is 15, then the sum of these 5 numbers is 5 × 15 = 75. The greatest possible integer would occur when four of the numbers are 1 and one of the numbers is 71. Enter 71.
  12. Substitute the function definition in f(2m) = 2f(m):
    f(2m) = 2f(m)
    (2m)² + 18 = 2(m² + 18)
    4m² + 18 = 2m² + 36
    2m² = 18
    m² = 9
    m = 3
    Enter 3.